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  • - [Narrator] So here's something that used to confuse me.

  • If you had two charges,

  • and we'll keep these straight by giving them a name.

  • We'll call this one Q1 and I'll call this one Q2.

  • If you've got these two charges sitting next to each other,

  • and you let go of them, they're gonna fly apart

  • because they repel each other.

  • Like charges repel, so the Q2's gonna get pushed

  • to the right,

  • and the Q1's gonna get pushed to the left.

  • They're gonna start gaining kinetic energy.

  • They're gonna start speeding up.

  • But if these charges are gaining kinetic energy,

  • where is that energy coming from?

  • I mean, if you believe in conservation of energy,

  • this energy had to come from somewhere.

  • So where is this energy coming from?

  • What is the source of this kinetic energy?

  • Well, the source is the electrical potential energy.

  • We would say that electrical potential energy

  • is turning into kinetic energy.

  • So originally in this system,

  • there was electrical potential energy,

  • and then there was less electrical potential energy,

  • but more kinetic energy.

  • So as the electrical potential energy decreases,

  • the kinetic energy increases.

  • But the total energy in this system,

  • this two-charge system, would remain the same.

  • So this is where that kinetic energy's coming from.

  • It's coming from the electrical potential energy.

  • And the letter that physicists typically choose

  • to represent potential energies is a u.

  • So why u for potential energy?

  • I don't know.

  • Like PE would've made sense, too,

  • because that's the first two letters

  • of the words potential energy.

  • But more often you see it like this.

  • We'll put a little subscript e

  • so that we know we're talking about

  • electrical potential energy

  • and not gravitational potential energy, say.

  • So that's all fine and good.

  • We've got potential energy turning into kinetic energy.

  • Well, we know the formula for the kinetic energy

  • of these charges.

  • We can find the kinetic energy of these charges

  • by taking one half the mass of one of the charges

  • times the speed of one of those charges squared.

  • What's the formula to find the electrical potential energy

  • between these charges?

  • So if you've got two or more charges

  • sitting next to each other,

  • Is there a nice formula to figure out

  • how much electrical potential energy there is

  • in that system?

  • Well, the good news is, there is.

  • There's a really nice formula

  • that will let you figure this out.

  • The bad news is, to derive it requires calculus.

  • So I'm not gonna do the calculus derivation in this video.

  • There's already a video on this.

  • We'll put a link to that so you can find that.

  • But in this video, I'm just gonna quote the result,

  • show you how to use it,

  • give you a tour so to speak of this formula.

  • And the formula looks like this.

  • So to find the electrical potential energy

  • between two charges, we take K, the electric constant,

  • multiplied by one of the charges,

  • and then multiplied by the other charge,

  • and then we divide by the distance

  • between those two charges.

  • We'll call that r.

  • So this is the center to center distance.

  • It would be from the center of one charge

  • to the center of the other.

  • That distance would be r, and we don't square it.

  • So in a lot of these formulas,

  • for instance Coulomb's law, the r is always squared.

  • For electrical fields, the r is squared,

  • but for potential energy, this r is not squared.

  • Basically, to find this formula in this derivation,

  • you do an integral.

  • That integral turns the r squared into just an r

  • on the bottom.

  • So don't try to square this.

  • It's just r this time.

  • And that's it. That's the formula to find

  • the electrical potential energy between two charges.

  • And here's something that used to confuse me.

  • I used to wonder, is this the electrical potential energy

  • of that charge, Q1?

  • Or is it the electrical potential energy of this charge, Q2?

  • Well, the best way to think about this

  • is that this is the electrical potential energy

  • of the system of charges.

  • So you need two of these charges

  • to have potential energy at all.

  • If you only had one, there would be no potential energy,

  • so think of this potential energy as the potential energy

  • that exists in this charge system.

  • So since this is an electrical potential energy

  • and all energy has units of joules if you're using SI units,

  • this will also have units of joules.

  • Something else that's important to know

  • is that this electrical potential energy is a scalar.

  • That is to say, it is not a vector.

  • There's no direction of this energy.

  • It's just a number with a unit that tells you

  • how much potential energy is in that system.

  • In other words, this is good news.

  • When things are vectors,

  • you have to break them into pieces.

  • And potentially you've got component problems here,

  • you got to figure out how much of that vector points right

  • and how much points up.

  • But that's not the case with electrical potential energy.

  • There's no direction of this energy,

  • so there will never be any components of this energy.

  • It is simply just the electrical potential energy.

  • So how do you use this formula?

  • What do problems look like?

  • Let's try a sample problem to give you some feel

  • for how you might use this equation in a given problem.

  • Okay, so for our sample problem,

  • let's say we know the values of the charges.

  • And let's say they start from rest,

  • separated by a distance of three centimeters.

  • And after you release them from rest,

  • you let them fly to a distance 12 centimeters apart.

  • And we need to know one more thing.

  • We need to know the mass of each charge.

  • So let's just say that each charge is one kilogram

  • just to make the numbers come out nice.

  • So the question we want to know is,

  • how fast are these charges going to be moving

  • once they've made it 12 centimeters away from each other?

  • So the blue one here, Q1, is gonna be speeding to the left.

  • Q2's gonna be speeding to the right.

  • How fast are they gonna be moving?

  • And to figure this out,

  • we're gonna use conservation of energy.

  • For our energy system, we'll include both charges,

  • and we'll say that if we've included everything

  • in our system,

  • then the total initial energy of our system

  • is gonna equal the total final energy of our system.

  • What kind of energy did our system have initially?

  • Well, the system started from rest initially,

  • so there was no kinetic energy to start with.

  • There would've only been electric potential energy

  • to start with.

  • So just call that u initial.

  • And then that's gonna have to equal the final energy

  • once they're 12 centimeters apart.

  • So the farther apart, they're gonna have less

  • electrical potential energy but they're still gonna have

  • some potential energy.

  • So we'll call that u final.

  • And now they're gonna be moving.

  • So since these charges are moving,

  • they're gonna have kinetic energy.

  • So plus the kinetic energy of our system.

  • So we'll use our formula for electrical potential energy

  • and we'll get that the initial electrical potential energy

  • is gonna be nine times 10 to the ninth

  • since that's the electric constant K

  • multiplied by the charge of Q1.

  • That's gonna be four microcoulombs.

  • A micro is 10 to the negative sixth.

  • So you gotta turn that into regular coulombs.

  • And then multiplied by Q2, which is two microcoulombs.

  • So that'd be two times 10 to the negative sixth

  • divided by the distance.

  • Well, this was the initial electrical potential energy

  • so this would be the initial distance between them.

  • That center to center distance was three centimeters,

  • but I can't plug in three.

  • This is in centimeters.

  • If I want my units to be in joules,

  • so that I get speeds in meters per second,

  • I've got to convert this to meters,

  • and three centimeters in meters is 0.03 meters.

  • You divide by a hundred,

  • because there's 100 centimeters in one meter.

  • And I don't square this.

  • The r in the bottom of here is not squared,

  • so you don't square that r.

  • So that's gonna be equal to

  • it's gonna be equal to another term

  • that looks just like this.

  • So I'm gonna copy and paste that.

  • The only difference is that now this is the final

  • electrical potential energy.

  • Well, the K value is the same.

  • The value of each charge is the same.

  • The only thing that's different is

  • that after they've flown apart,

  • they're no longer three centimeters apart,

  • they're 12 centimeters apart.

  • So we'll plug in 0.12 meters,

  • since 12 centimeters is .12 meters.

  • And then we have to add the kinetic energy.

  • So I'm just gonna call this k for now.

  • The total kinetic energy of the system

  • after they've reached 12 centimeters.

  • Well, if you calculate these terms,

  • if you multiply all this out on the left-hand side,

  • you get 2.4 joules of initial electrical potential energy.

  • And that's gonna equal,

  • if you calculate all of this in this term,

  • multiply the charges, divide by .12

  • and multiply by nine times 10 to the ninth,

  • you get 0.6 joules of electrical potential energy

  • after they're 12 centimeters apart

  • plus the amount of kinetic energy in the system,

  • so we can replace this kinetic energy of our system

  • with the formula for kinetic energy,

  • which is gonna be one half m-v squared.

  • But here's the problem.

  • Both of these charges are moving.

  • So if we want to do this correctly,

  • we're gonna have to take into account

  • that both of these charges are gonna have kinetic energy,

  • not just one of them.

  • If I only put one half times one kilogram times v squared,

  • I'd get the wrong answer

  • because I would've neglected the fact that the other charge

  • also had kinetic energy.

  • So we could do one of two things.

  • Since these masses are the same,

  • they're gonna have the same speed,

  • and that means we can write this mass here

  • as two kilograms times the common speed squared

  • or you could just write two terms, one for each charge.

  • This is a little safer.

  • I'm just gonna do that.

  • Conceptually, it's a little easier to think about.

  • Okay, so I solve this.

  • 2.4 minus .6 is gonna be 1.8 joules,

  • and that's gonna equal one half times one kilogram

  • times the speed of that second particle squared

  • plus one half times one kilogram times the speed

  • of the first particle squared.

  • And here's where we have to make that argument.

  • Since these have the same mass,

  • they're gonna be moving with the same speed.

  • One half v squared plus one half v squared

  • which is really just v squared,

  • because a half of v squared plus a half of v squared

  • is a whole of v squared.

  • Now if you're clever, you might be like, "Wait a minute.

  • "This charge, even though it had the same mass,

  • "it had more charge than this charge did.

  • "Isn't this charge gonna be moving faster

  • "since it had more charge?"

  • No, it's not.

  • The force that these charges are gonna exert on each other

  • are always the same, even if they have different charges.

  • That's counter-intuitive, but it's true.

  • Newton's third law tells us that has to be true.

  • So if they exert the same force on each other

  • over the same amount of distance,

  • then they will do the same amount of work on each other.

  • And if they have the same mass,

  • that means they're gonna end with the same speed

  • as each other.

  • So they'll have the same speed, a common speed we'll call v.

  • So now to solve for v, I just take

  • a square root of each side and I get that the speed

  • of each charge is gonna be the square root of 1.8.

  • Technically I'd have to divide that joules

  • by kilograms first, because even though this was a 1,

  • to make the units come out right

  • I'd have to have joule per kilogram.

  • And if I take the square root, I get 1.3 meters per second.

  • That's how fast these charges are gonna be moving

  • after they've moved to the point

  • where they're 12 centimeters away from each other.

  • Conceptually, potential energy was turning into

  • kinetic energy.

  • So the final potential energy was less

  • than the initial potential energy,

  • and all that energy went into the kinetic energies

  • of these charges.

  • So we solved this problem.

  • Let's switch it up.

  • Let's say instead of starting these charges from rest

  • three centimeters apart,

  • let's say we start them from rest 12 centimeters apart

  • but we make this Q2 negative.

  • So now instead of being positive 2 microcoulombs,

  • we're gonna make this negative 2 microcoulombs.

  • And now that this charge is negative,

  • it's attracted to the positive charge,

  • and likewise this positive charge is

  • attracted to the negative charge.

  • So let's say we released these from rest

  • 12 centimeters apart,

  • and we allowed them to fly forward to each other

  • until they're three centimeters apart.

  • And we ask the same question,

  • how fast are they gonna be going when they get to this point

  • where they're three centimeters apart?

  • Okay, so what would change in the math up here?

  • Since they're still released from rest,

  • we still start with no kinetic energy,

  • so that doesn't change.

  • But this time, they didn't start three centimeters apart.

  • So instead of starting with three and ending with 12,

  • they're gonna start 12 centimeters apart

  • and end three centimeters apart.

  • All right, so what else changes up here?

  • The only other thing that changed was the sign of Q2.

  • And you might think, I shouldn't plug in the signs

  • of the charges in here,

  • because that gets me mixed up.

  • But that was for electric field and electric force.

  • If these aren't vectors, you can plug in positives

  • and negative signs.

  • And you should. The easiest thing to do

  • is just plug in those positives and negatives.

  • And this equation will just tell you

  • whether you end up with a positive potential energy

  • or a negative potential energy.

  • We don't like including this in the electric field

  • and electric force formulas

  • because those are vectors,

  • and if they're vectors, we're gonna have to decide

  • what direction they point and this negative can screw us up.

  • But it's not gonna screw us up in this case.

  • This negative is just gonna tell us

  • whether we have positive potential energy

  • or negative potential energy.

  • There's no worry about breaking up a vector,

  • because these are scalars.

  • So long story short, we plug in the positive signs

  • if it's a positive charge.

  • We plug in the negative sign if it's a negative charge.

  • This formula's smart enough to figure it out,

  • since it's a scalar, we don't have to worry about

  • breaking up any components.

  • In other words, instead of two up here,

  • we're gonna have negative two microcoulombs.

  • And instead of positive two in this formula,

  • we're gonna have negative two microcoulombs.

  • So if we multiply out the left-hand side,

  • it might not be surprising.

  • All we're gonna get is negative 0.6 joules

  • of initial potential energy.

  • And this might worry you.

  • You might be like, "Wait a minute,

  • "we're starting with negative potential energy?"

  • You might say, "That makes no sense.

  • "How are we gonna get kinetic energy out of a system

  • "that starts with less than zero potential energy?"

  • So it seems kind of weird.

  • How can I start with less than zero or zero potential energy

  • and still get kinetic energy out?

  • Well, it's just because this term,

  • your final potential energy term,

  • is gonna be even more negative.

  • If I calculate this term, I end up with negative 2.4 joules.

  • And then we add to that the kinetic energy of the system.

  • So in other words, our system

  • is still gaining kinetic energy

  • because it's still losing potential energy.

  • Just because you've got negative potential energy

  • doesn't mean you can't have less potential energy

  • than you started with.

  • It's kind of like finances.

  • Trust me, if you start with less than zero money,

  • if you start in debt,

  • that doesn't mean you can't spend money.

  • You can still get a credit card and become more in debt.

  • You can still get stuff, even if you have no money

  • or less than zero money.

  • It just means you're gonna go more and more in debt.

  • And that's what this electric potential is doing.

  • It's becoming more and more in debt

  • so that it can finance an increase in kinetic energy.

  • Not the best financial decision, but this is physics,

  • so they don't care.

  • All right, so we solve this for the kinetic energy

  • of the system.

  • We add 2.4 joules to both sides

  • and we get positive 1.8 joules on the left hand side

  • equals

  • We'll have two terms because they're both gonna be moving.

  • We'll have the one half times one kilogram

  • times the speed of one of the charges squared

  • plus one half times one kilogram times the speed

  • of the other charge squared,

  • which again just gives us v squared.

  • And if we solve this for v, we're gonna get the same value

  • we got last time, 1.3 meters per second.

  • So recapping the formula for the electrical potential energy

  • between two charges is gonna be

  • k Q1 Q2 over r.

  • And since the energy is a scalar,

  • you can plug in those negative signs

  • to tell you if the potential energy is positive or negative.

  • Since this is energy, you could use it in conservation

  • of energy.

  • And it's possible for systems to have

  • negative electric potential energy,

  • and those systems can still convert energy

  • into kinetic energy.

  • They would just have to make sure

  • that their electric potential energy becomes

  • even more negative.

- [Narrator] So here's something that used to confuse me.

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