We'lltalkaboutonehere, um, that I learnedwhen I wasinhighschoolandtheseeminglymiraculousmethodstosolveit, whichismyfavoritethingfromthetrainingfortheInternationalMathOlympiadbackinBulgaria.
If I addthetwoshorteronce, I mustgetthelongeronelookback, a dollarMystereandwe'realmostdoingsomethingsimilarwherehavingtwothingsongetting 1/3 1 Indeed, thisbethesamesituation, whichin a differentworldinaninvertedworldintheanswerisyes.
Nowyou'rethinking I shoulddrawthecircleofinversion.
I don't haveto.
Actually, all I careisabouttheshapesoffiguresafterinversion, notexactlywheretheylocate.
So I thinkyou'regreat.
Thiscirclethroughthecenterofinversionwillturninto a linenotthroughthecenter, so I canjustbeboldanddraw a linenotthroughthecenterofinversioninDeclarethatmycirclegoesthere.
Whynotnowwewanttoquicklyfigureoutwheredothepoints a d, c and B go.
Theyhave a G twiceandCDtwiceand B D twice, sowewillmultiplyeverythingby 80 times.
Bi G TimeSudiThat's thecommon.
Donotnowif I multiplythisfractionbythisproductwill, inessence, counselthewholedenominatorandtheonlythingthatwillbeleftmultiplythisCDsothatCDmustbemultipliedby a B.
We'lltalkaboutonehere, um, that I learnedwhen I wasinhighschoolandtheseeminglymiraculousmethodstosolveit, whichismyfavoritethingfromthetrainingfortheInternationalMathOlympiadbackinBulgaria.
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