So let's say I have a spring.

Let me draw the ground so that we know what's going on with

the spring.

So let me see, this is the floor.

That's the floor, and I have a spring.

It's along the floor.

I'll use a thicker one, just to show it's a spring.

Let's say the spring looks something like this.

Whoops, I'm still using the line tool.

So the spring looks like this.

This is my spring, my amazingly drawn spring.

Let's say at this end it's attached to a wall.

That's a wall.

And so this is a spring when I don't have any force acting on

it, this is just the natural state of the spring.

And we could call this, where it just naturally rests, this

tip of the spring.

And let's say that when I were to apply a force of 5 Newtons

into the spring, it looks something like this.

Redraw everything.

So when I apply a force of 5 Newtons-- I'll draw the wall

in magenta now.

When I apply a force of 5 Newtons, the

spring looks like this.

It compresses, right?

We're all familiar with this.

We sit on a bed every day or a sofa.

So let's say it compresses to here.

If this was the normal resting-- so this is where the

spring was when I applied no force, but when I applied 5

Newtons in that direction, let's say that this distance

right here is 10 meters.

And so a typical question that you'll see, and we'll explain

how to do it, is a spring compresses or elongates when

you apply a certain force by some distance.

How much will it compress when you apply a different force?

So my question is how much will it compress when I apply

a 10-Newton force?

So your intuition that it'll compress more is correct, but

is it linear to how much I compress it?

Is it a square of how much I compress it?

How does it relate?

I think you probably could guess.

It's actually worth an experiment.

Or you could just keep watching the video.

So let's say I apply a 10-Newton force.

What will the spring look like?

Well, it'll be more compressed.

Drop my force to 10 Newtons.

And if this was the natural place where the spring would

rest, what is this distance?

Well, it turns out that it is linear.

What do I mean by linear?

Well, it means that the more the force-- it's equally

proportional to how much the spring will compress.

And it actually works the other way.

If you applied 5 Newtons in this direction, to the right,

you would have gone 10 meters in this direction.

So it goes whether you're elongating the spring or

compressing the spring within some reasonable tolerance.

We've all had this experience.

If you compress something too much or you stretch it too

much, it doesn't really go back to where it was before.

But within some reasonable tolerance, it's proportional.

So what does that mean?

That means that the restoring force of the spring is minus

some number, times the displacement of the spring.

So what does this mean?

So in this example right here, what was the displacement of

the spring?

Well, if we take positive x to the right and negative x to

the left, the displacement of the spring was what?

The displacement, in this example right here, x is equal

to minus 10, right?

Because I went 10 to the left.

And so it says that the restorative force is going to

be equal to minus K times how much it's

distorted times minus 10.

So the minuses cancel out, so it equals 10K.

What's the restorative force in this example?

Well, you might say, it's 5 Newtons, just because that's

the only force I've drawn here, and you would be to some

degree correct.

And actually, since we're doing positive and negative,

and this 5 Newton is to the left, so to the negative

x-direction, actually, I should call this minus 5

Newtons and I should call this minus 10 Newtons, because

obviously, these are vectors and we're going to the left.

I picked the convention that to the left means negative.

So what's the restorative force?

Well, in this example-- and we assume that K is a positive

number for our purposes.

In this example, the restorative force is a

positive number.

So what is the restorative force?

So that's actually the force, the counteracting force, of

the spring.

That's what this formula gives us.

So if this spring is stationary when I apply this

5-Newton force, that means that there must be another

equal and opposite force that's

positive 5 Newtons, right?

If there weren't, the spring would keep compressing.

And if the force was more than 5 Newtons, the spring would go

back this way.

So the fact that I know that when I apply a 5-Newton force

to the left, or a negative 5-Newton force, the spring is

no longer moving, it means that there must be-- or no

longer accelerating, actually, it means that there must be an

equal and opposite force to the right, and that's the

restorative force.

Another way to think about it is if I were to let-- well, I

won't go in there now.

So in this case, the restorative force is 5

Newtons, so we can solve for K.

We could say 5 is equal to 10K.

Divide both sides by 10.

You get K is equal to 1/2.

So now we can use that information to figure out what

is the displacement when I apply a

negative 10-Newton force?

When I push the spring in with 10 Newtons in

the leftward direction?

So first of all, what's the restorative force here?

Well, if the spring is no longer accelerating in either

direction, or the tip of the spring is no longer

accelerating in either direction, we know that the

restorative force must be counterbalancing this force

that I'm compressing with, right?

The force that the spring wants to expand back with is

10 Newtons, positive 10 Newtons, right?

And we know the spring constant, this K for this

spring, for this material, whatever it might be, is 1/2.

So we know the restorative force is equal to 1/2 times

the distance, right?

And the formula is minus K, right?

And then, what is the restorative

force in this example?

Well I said it's 10 Newtons, so we know that 10 Newtons is

equal to minus 1/2x.

And so what is x?

Well, multiply both sides by minus 1/2, and

you get minus 20.

I'm sorry, multiply both sides by minus 2, you get minus 20

is equal to x.

So x goes to the left 20 units.

So that's all that it's telling us.

And this law is called Hooke's Law, and it's named after--

I'll read it-- a physicist in the 17th century, a British

physicist. And he figured out that the amount of force

necessary to keep a spring compressed is proportional to

how much you've compressed it.

And that's all that this formula says.

And that negative number, remember, this formula gives

us the restorative force.

So it says that the force is always in the opposite

direction of how much you displace it.

So, for example, if you were to displace this spring in

this direction, if you were to apply a force and x were a

positive and you were to go in that direction, the force-- no

wait, sorry.

This is where the spring rests.

If you were to apply some force and take the spring out

to here, this negative number tells us that the spring will

essentially try to pull back with the restorative force in

the other direction.

Let's do one more problem and I think this

will be clear to you.

So let's say I have a spring, and all of these problems kind

of go along.

So let's say when I apply a force of 2 Newtons, so this is

what I apply when I apply a force of 2 Newtons.

Well, let's say it this way.

Let's say when I stretch the spring.

Let's say this is the spring, and when I apply a force of 2

Newtons to the right, the spring gets stretched 1 meter.

So first of all, let's figure out what K is.

So if the spring is stretched by 1 meter, out here, its

restorative force will be 2 Newtons back this way, right?

So its restorative force, this 2 Newtons, will equal minus K

times how much I displaced it.

Well I, displaced it by 1 meter, so then we multiply

both sides by negative 1, and we get K is equal to minus 2.

So then we can use Hooke's Law to note the equation for

this-- to figure out the restorative force for this

particular spring, and it would be minus 2x.

And then I said, well, how much force would I have to

apply to distort the spring by 2 meters?

Well, it's 2 times 2, it would be 4.

4 Newtons to displace it by 2 meters, and, of course, the

restorative force will then be in the opposite direction, and

that's where we get the negative number.

Anyway, I've run out of time.

I'll see you in the next video.