Subtitles section Play video Print subtitles >> All right what I'd like to do today and on Monday is to talk about NMR spectroscopy and kind of how NMR spectroscopy works. I'll call it concepts in theory and for me what I want to do is give my perspective on NMR which is not a highly mathematical perspective. In fact, everything I write up here today is going to really be in terms of numbers is actually going to be simple arithmetic and most of it is more an embodiment of the idea rather than a specific calculation that you quote need to do. So where NMR begins is with the concept that a nucleus of certain sorts and I'll just write a proton for now, has a spin to it and when you have a spinning charge it generates a magnetic dipole. And if you apply a magnetic field, we'll call that magnetic field B naught, then you have two different spin states or more and you'll see examples of this in the case of nuclear quadrupoles but let's start with the case of a proton or a C 13. You have two spin states that can exist, quanti-spin states. The spin of the nucleus can either be spin up, so if it's spin up, in other words in the same direction as the applied magnetic field then this is going to be lower in energy so I'll put, by up I mean aligned with B naught and if it's spin down meaning aligned against B naught then we're higher in energy and we'll refer to throughout our discussion. We'll refer to the lower energy state as the alpha state and to the higher energy state as the beta state. Now different types of nuclei have different spin properties. Rather than trying to start with generalizations about rules I'll come to those in a moment because at some point you'll be wondering in your project well could I study chlorine 35 or something like that, let's just start with typical nuclei studied. So if you go for example, to the 400 megahertz NMR spectrometer in my building in Natural Sciences 1, you'll find that that instrument can study protons. I'm going to write a couple of numbers for these. I'm going to write the atomic number and the mass number. And it can study C 13 and it can study F 19 and it can study P 31. And these are common nuclei that are often studied by NMR. They're easy to study. What do these nuclei have in common? They have a one-half indeed and what, forgetting their spin state what property on the blackboard do they have in common? >> Odd numbers of protons and neutrons. Odd numbers of protons and neutrons or more specifically we can group them that their mass number is odd, specifically that the sum of their protons and neutrons is odd. So nuclei with an odd mass number have a nuclear spin and the quantum characterization of nuclear spin is what's called a spin number and we'll call the spin number i. It really doesn't matter what we call it but they call it i and so that number is going to be one-half and that gives you all the ones up here but if we want a generalize more nuclei with an odd mass number will have a spin number of one-half or three-halves or five-halves, etcetera. So that's the more general idea. The ones with one-half are easy because they have what's called the nuclear dipole. If you have three-halves or five-halves or one as we'll see in just a moment you have what's called a nuclear quadrupole and then those tend to be harder. So all the ones here of i equals one-half have spin states so we have the quantum number and then the two spin states they can have and so the spin states are plus or minus one-half. So that's all of these H 1, C 13, oops, F 19 we'll come to nitrogen in just a second and P 31. Now a nucleus with a spin number of three-halves can have spin states of plus or minus one-half or plus or minus three-halves and this is what you call a nuclear quadrupole. Most of the time, many of the times nuclei with nuclear quadrupoles don't behave as if they're NMR active. In our next lecture we'll get to the concept of relaxation. Relaxation basically is how quickly you flip between the two spin states or in this case, between the four spin states or three in some cases and often they flip very quickly which means you can't study them by NMR. Relaxation is affected by properties like symmetry as well and I'll get to that in a moment with another example. But if I give I an example of a nucleus with a spin state of three halves, of boron there are two different isotopes. There are B 10 and B 11 and B 11 has, I think they both do but B 11 has a spin state of three-halves and if you look at the NMR spectrum of borohydride from this one what you see in the H1 NMR is you see four lines equally spaced and of equal height due to the hydrogens coupling with the nuclear quadrupole and it's very unusual because normally we think about splitting into a doublet or if you're thinking a triplet or a one to two to one triplet or quartet or one to three to three to one triplet, but what's happening here is the hydrogen C boron and they see either the boron having a spin state of negative three-halves or negative one-half or positive one-half or positive three-halves and so you see the four spin states and that gives are rise to four lines. All right but so let's look at some other nuclei with an odd mass number. [ Silence ] So one very important nucleus in biomolecular NMR is N 15. Nitrogen 15 has a spin number of i equals one and indeed N 15 is often studied. Most nitrogens, not N 15. We talked about this when we talked about mass spectrometry we said that the natural abundance of N 15 is 0.38 percent and that's really, really low. The isotopic abundance of C 13 spin active is one-and a half percent is 1.1 percent and you know that carbon NMR is not very sensitive. You need to have a reasonable sample size, more than you have for protein typically and sometimes often collect data for much longer. Well by the time you're down to .38 percent studying it at natural abundance is pretty hard so often you do this with isotopic labeling. Two dimensional N 15 based techniques are a mainstay of protein NMR spectroscopy and in general since most proteins are expressed these days what you do is you simply grow up your e-coli with N 15 ammonium chloride and they absorb that and use it to make up the amino acids and then you can get a fully N 15 labeled protein which is very useful. N 15 is starting to become more important in some natural product structure determination. Alkaloids as you may have seen for example in Neil Gard's [assumed spelling] talks have lots of nitrogens in them and so being able to figure out the positions of those nitrogens can be very important. In the case of something like an alkaloid or a synthetic project you might not be able to put N 15 in and NMR spectrometers are becoming more sensitive and so it becomes not completely nuts to think about using N 15 techniques in your NMR. At the end of the course I may talk about some two the dimensional techniques with N 15 at natural abundance that people are doing just because I think it's useful but that won't be until the end of November or December. Another common, well not common, another nucleus is oxygen, O 17 remember we said is only low natural abundance. It's only very low I should say. It's only.04 percent and oxygen 17 has a spin number of i is equal to five-halves so that's a nucleus that can have six spin states, negative five-halves, negative three-halves, negative one-half, positive one-half, three-halves, five-halves, etcetera and so it has sort of doubly damned and so it's not generally studied. All right so that takes care of our nuclei with odd mass numbers. Now the next class I'll talk about is if you have an even mass number and an even atomic number so that's easy those are nuclei like C 12, O 16 and the answer is very simple. Those have a spin number of i equal zero. They have no spin and those are NMR inactive. Since you don't have different spin states you can't have quanti-transitions between spin states so there's no way they can be studied by NMR spectroscopy. So the last class then becomes nuclei with an even mass number but not atomic number so that would include nuclei like deuterium, nuclei like N 14. I guess that would be the common ones we'd encounter in organic compounds. These all have a nuclear quadrupole. Remember a quadrupole is anything that doesn't have a dipole, i.e. just spin up, spin down, i.e. i equally one-half so these all have a nuclear quadrupole and a spin number i equals 1, 2, 3, etcetera so for example, if you take deuterium you have a spin number i equals 1 and so you have three spin states available to it and you know the direct manifestation of this that many of you have seen with your own eyes? Who's run a C 13 NMR, most of you? What solvent did you use? Chloroform, right, the first solvent most of us reach for because it's pretty cheap as solvents go and pretty good at dissolving organic chemicals. It's cheap because it doesn't have that much deuterium in it, right? You only have one deuterium for all that weight of chlorine. You need to deuterium to get the deuterium lock for NMR spectroscopy and what do you always see when you run an NMR spectrum in deuterochloroform? >> A triplet? >> A triplet and a very interesting sort of triplet so for CDCl 3 in the C 13 NMR you see a one-to-one-to-one triplet centered at 77 ppm. >> These are really jammed together. >> It's really jammed together. The separation between the lines is 32 hertz, in other words the distance between these two lines is 32 hertz. The distance between these two lines is 32 hertz. If you're running your spectrum on a 500 megahertz spectrometer that means the carbon NMR is running at a 125.7 megahertz. I'll come back to that in a second which means 1 ppm is 125 hertz which means the lines here are separated by about three-tenth of a ppm and that's on a big roughly 200 ppm scale so as James said those lines are really close together and the manifestation is it's a one-to-one-to-one triplet because to a first order approximation a third of your deuterons are in spin state negative one. A third of your deuterons are in spin state zero and a third of your deuterons are in a spin state of positive one and we'll see in a moment that they're minuscule, minuscule differences in the population of the spin states and that's really, really important. We'll also see in a moment that that number 32 comes back when we see something else. All right most of the time-- so deuterium is kind of special among nuclear quadrupoles in that most of the time nuclear quadrupoles, nuclei with quadrupoles undergo rapid relaxation but deuterium is special. It's relaxation is slow and I'll just say to put it in simple terms is effectively like NMR inactive. So many of the nuclei with nuclear quadrupoles like chlorine 35 and chlorine 37 how do we know that those have, all right I will take that back. We can't know that they have a nuclear dipole or a nuclear quadrupole but we know they have a spin number of one-half or three-halves or five-halves or seven-halves. They happen to have the higher ones so we never see J coupling. We never see spin-spin coupling to chlorine 35 or chlorine 37, if we did your carbon spectrum here, your C 13 NMR spectrum would actually be much more complicated because you'd be seeing splitting from the chlorines. Okay, so nitrogen 15, I'm sorry nitrogen 14 also has a nuclear quadrupole. It has a spin number of i equals 1 and so normally you have rapid relaxation, so for example, if we come to that amide what we were dealing with before when I asked you about the IR spectrum and if we look at the NMR spectrum of this amide of course most of your nitrogen, 99.62 percent of your nitrogen virtually all is N 14 in here and we don't see J coupling to this proton so as I said the fact that we do see J coupling between the deuterium, J coupling just means spin-spin coupling to the C 13 is because deuterium is the odd ball here and that it often doesn't undergo relaxation but most nuclei with a nuclear quadrupole don't show nuclear coupling because we have rapid relaxation. As I was saying earlier with my example of borohydride symmetry is the odd ball on or highly symmetric species end up being odd balls in that you have slow relaxation so borohydride B H 4 minus has tetrahedral symmetry so you see coupling from the boron to the hydrogens a case that you may see and I saw first by accident one of those cases where you simply dissolve out the compound in a solution and you get an NMR spectrum and so this is ammonium chloride in DMSO, ammonium chloride has NH 4 plus Cl minus and the ammonium has tetrahedral symmetry and the first time I happen the accidentally have this in a sample and took an NMR spectrum as I said in DMSO D6, I saw an NMR spectrum with 3 peaks that were so far apart that you barely could tell they went together except the odd thing was they were all the same height and this spacing was the same as that and it was what's going on? Oh, wait that's your nitrogen so this is your J 1 NH. In other words your one bond coupling between the nitrogen and the hydrogen and I don't remember what the coupling constant is but it's big. >> It was always produced as J no matter? >> J is, yeah J is the term that we use to refer to spin-spin coupling. >> That's not just from proton NMR, right? >> That's not just proton NMR. So we would describe this as J 1 CD equals 32 hertz. And later on when we start to talk about 2D techniques like HMQC and HMBC. Terms like J 1 CH, J 2 CH and J 3 CH, in other words one bond, two bond and three bond carbon hydrogen couplings will become are very important in structure determination. All right so when we last left our spinning nuclear dipole he was spinning in the presence of an applied magnetic field and I said there were two states, the alpha state and the beta state and the alpha state was lower in energy than the beta state so I can make a little diagram, E and I can show just like you learned in electronic structure where you learned for example, you have pi orbitals and pi star orbitals and you have populated electrons in your two orbital. Here we can think about populations of nuclei. It's a little bit different in a sense we're talking over the entire sample but if we have our applied magnetic field B naught and we have our alpha state and our beta state, remember the alpha state is aligned with magnetic field, we can think about some nuclei being in the alpha state and some nuclei being in the beta state and there's an energy gap between these two spin states and we can think about the energy to flip a nucleus from the alpha state to the beta state as the energy of a photon, in other words an energy quantum in the electromagnetic spectrum and that delta E is going to be H NU. In other words the energy, the difference, the frequency of a photon to flip a nucleus from the alpha state to the beta state is going to be dictated by that difference in energy such that E equals H NU, delta E equals H NU. Now what sort of energies are we talking about? Well we're talking about 500 megahertz for protons so we're talking about radio frequency, so let me just give you a calibration here. So if you think about UV and our delta E so maybe if I think about UV and I think about a chromophore, maybe I think about my mercury line at 254 nanometers from my TLC lamp and I think about a chromophore say containing a benzene ring or a methoxybenzene ring and maybe I say all right, if we just take 254 nanometers and I go ahead and plug into you remember C equals lambda NU so that's our wavelength and you calculate NU the frequency and then you calculate E equals H NU and you plug in the Planck's constant you get the detective to E corresponding to a photon in the UV is 113 kilocalories per mole. And then you stop and you think like an organic chemist and you say okay, wait what's 113 kilocalories per mole? What's the difference between a pi and a pi star? It's a little stronger than the strength of a carbon-carbon single bond, a little stronger than the strength of a carbon hydrogen bond in other words the energy difference in the UV spectrum corresponds to the strength of bonds. And now if you think about, so this is our UV, if we think about UV, oh, I guess I wrote UV. All right if we think about IR and I think about a typical stretch, well we've been talking a lot about carbonyls. Carbonyls absorb at about 1700 wave numbers. We said that wave numbers was centimeters per wave which meant your wavelength is 117 hundredth of a centimeter and that's lambda and then you calculate your frequency out and it's in the infrared range and then you plug in to equal delta equals H NU and you find out that delta E is equal to 4.87 kilocalories per mole. And you say okay that kind of makes sense. I know that infrared is lower in energy than UV. It's lower in energy than visible. I know that we don't have sufficient energy to break bonds in the IR. Indeed all we're doing is kicking them up a higher vibrational state and you remember you're energy curves with your vibrational states and it takes many jumps before you get to the point that you're dissociating bonds. Well if we do the same for NMR and let's say we take 500 megahertz and we plug in and again plug in E equals H NU then delta E is equal to 0.0477 but it's not kilocalories per mole. It's calories per mole. So the first thing when you see NMR spectroscopy is you're getting dinged badly because the technique involves very little energy absorbent. In other words when you're measuring a UV spectrum it's very easy for a detector to detect the energy of a photon and when you're measuring an IR spectrum it's very easy. And already your detectors have to be much more sensitive and it's going to get worse from there. All right so we talked about delta equals H NU, what's new for a-- that's not a pun, if it were it would be terrible. What's new for a nucleus? NU is dictated by gamma B naught over 2 pi. Okay, well so far so good. I said B naught is the applied magnetic field so if you look at this you'd say well this kind of makes sense bigger applied magnetic field means bigger difference in energy, right? Delta equals H times gamma B naught over 2 pi so that kind of makes sense. All right let's just take a look at that. What does that mean? There's a linear proportionality, so if I again plug into this equation I get that, so in other words if I just go ahead and plug into this equation I'll come back to gamma in a second. We find out that if we apply 70, 500 gauss magnetic field that leads to 300 megahertz for H 1. If we go to a higher magnetic field that leads to a higher frequency and it's going to be in a linear fashion so if I apply 117, 500 gauss magnetic field now we're at a 500 megahertz NMR spectrometer and if you make a 300 megahertz NMR spectrometer you have an electromagnet like this maybe this big, super-conducting magnet this big where you have a coil of wire with electricity passing through it, in liquid helium in the wire is super-conducting so the electricity flows and flows and flows without any resistance or diminution and you get a strong magnetic field. In order to build the technology to get a uniform 117, 500 gauss magnetic field you need a kettle about this big across and about this high to house the super-conducting magnet and the liquid helium and the shims and so forth and finally if you get to say an 800 megahertz and of course it's all linear proportionality you're going to have a 188, 000 gauss magnetic field and that is close to as big as can currently be made uniform so now you'll have a magnet that's even bigger and needs to have its own room in order to house it and flux lines that go very far out and the limits on commercial instruments these days are about 900 megahertz and the thing costs, I guess ours cost about for to whole thing about 2 and a half million dollars at a time you're at 900 megahertz it's many, many millions of dollars and there may be one, I think one gigahertz out there but we really for now at least seem to-- what? >> In France or something. >> I think so. We really seem to have just pushed the limits of technology for how much electricity you can put in a super-conducting coil without it just ripping itself apart. All right so the other quantity we have in this equation is gamma. Gamma is called the magnetogyric ratio sometimes you'll hear it referred to as the gyromagnetic ratio. This is a property of the individual nucleus. The bigger the gyromagnetic ratio, the bigger the magnetogyric ratio effectively the bigger the nuclear spin, the bigger the magnet that the nucleus is. Protons actually are good. They have one of the biggest magnetogyric ratio of any nuclei studied 26, 750 and it's 53. What am I thinking here? And so just to put this into context at 117, 500 gauss in other words the relatively large magnet, so at 117, 500 gauss you have the nuclei flips its spin at 500 megahertz. If we look at C 13 we get a gyromagnetic ratio of 6, 728 and that corresponds to absorbing energy at a frequency of 125.74 megahertz on this 117, 000 gauss magnet. So one of the implications, remember I said you were dealing with very small energy differences. One of the implications is the energy differences are even smaller for carbon than for proton so now you're getting doubly damned for carbon because the national abundance for C 13 is only 1.1 percent so most of your carbons aren't even C 13. Indeed with small molecules most of your molecules don't even contain one C 13 in them. We saw that in mass spec where you see the C 13 isotopomer peak and for the small molecules that we were looking at that peak is small compared to the C 13 isotopomer peak but you're getting damned again because its small magnetogyric ratio leads to smaller energy absorption. Now the other thing you have to remember is even though you're recording your C 13 NMR spectrum on a quote 500 megahertz NMR spectrometer you're not reporting your carbon NMR on at 500 megahertz, if you were you'd be that lucky person not in France but maybe on Mars who has access to a two gigahertz NMR spectrometer and there ain't no such animal right now. All right fluorine 19 isn't so bad. Its magnetogyric ratio is 25, 179 so that corresponds on the same spectrometer to 470, 000, 470.58 megahertz. Usually it takes certain types of probe technology. We'll talk more about that later but certain types of coil technology to tune to higher frequencies and certain type of coil technology to tune to lower frequencies. So often if you want a really good proton NMR you will use a special probe where the coil that's tuned for proton is inner and close to the sample and the coil that's tuned for other nuclei is bigger and further away from the sample. That sort of probe won't be as good for carbon 13 because you have the coils further away from the sample, the coil that's good for C 13. Conversely, if you find that Phil Dennison has put a broadband probe in the spectrometer where the nucleus at the lower frequency is inside in the coil you may find that the proton NMR collects is not as good or is not as sensitive or is not as sharp and well shimmed because the coil is further out. Fluorine is interesting because often you can use the same coil for both fluorine and for proton. Phosphorus also has a smaller magnetogyric ratio. It's 10, 840. Now remember fluorine and phosphorus have all of their naturally occurring nuclei as F 19 and all of their naturally occurring nuclei as P 31 so these are not damned by the low isotopic abundance the way phosphorus is. Another nucleus that's sometimes studied is deuterium. Deuterium we talked about the nuclear quadrupole. You also have your lock coil in there. The magnetogyric ratio for deuterium is 4,107 so that means your lock frequency on this spectrometer is at 76.76 megahertz. [ Silence ] [ Inaudible student question ] So the cryoprobe technology is really wonderful. What they've done in the cryoprobe technology is they have cooled the probe and it's either, I guess it's not a super-conducting probe but what it is is a very low noise probe. And because the electronics of the probe are cooled so you don't get much electronic noise and the result is it's very high sensitivity. And we were fortunate that had just, when we bought it they had just developed technology that had both carbon and proton sensitivity and basically special coil technology so that instrument is super good for proton. It's got a huge, just an incredible signal to noise ratio, better than even the 800 megahertz spectrometer. It's also super good for carbon. I want to come back to these magnetogyric ratios because you've seen this with your own eyes. Now we already talked about the coupling, the J 1 CD coupling in chloroform and remember I said you see this one-to-one-to-one triplet in the C 13 NMR and the separation of the lines is 32 hertz. Well if you've ever looked hard at your chloroform peak in the proton NMR, so here we have DC coupling, our H2 coupling but if you ever looked hard at the chloroform peak in the proton NMR what you see is something like this. You see a main peak for your CH and of course what you're looking at is chloroform but you'll also see two peaks here that are the C 13 satellites and those correspond so this is your C 12 peak and those correspond to the J coupling to the C 13. In other words what you're seeing here is a doublet and the separation of those two lines is 209 hertz and the mathematical relationship between 209 and 32 is the same as the mathematical relationship, the ratio between 26,753 and 4107. In other words it's 6.5, in other words the magnetogyric ratio is 6.5 times bigger for a proton than for a deuteron and we see that directly in the J coupling. The effect of the magnet that the deuterium has in splitting the carbon is one-sixth point fifth the effect that the carbon has in splitting the proton because coupling is mutual. All right the last thing I want to talk about I've talked about how damned we are by energy being low. I've talked in the case of carbon about isotopic abundance but now the really damning thing ends up being the Boltzmann distribution. That is the population of the spin states. In the case of a benzene all of your molecules are in the ground electronic state. In the case of a ketone all of your carbonyls are in the ground vibrational state but in the case of nuclei the energy difference between the alpha and beta states is so small that both are populated and if you think back to your P chem and you calculate the number in the beta state versus the alpha state that's going to correspond to the difference in energy, delta E over KT where K is the Boltzmann constant and then if we just remember that delta E equals H NU is equal to H times gamma times B naught over 2 pi and then we say, okay let's just take at 70,500 gauss, that's our 300 megahertz and let's plug in N beta divided by N alpha is equal to and if I plug in that's E to the negative 6.63 times 10 to the negative 34 times the magnetogyric ratio 236753 times 70,500 applied magnetic field over 2 pi divided by our Planck's constant of 1.38 times 10 to the negative 23 and let's say we're saying at 298 Kelvin. So I say 298 here and when I work that all out what I get is this number comes out to a quotient that's very, very, very close to one .999952. Four nines and five two corresponds to the ratio in the beta state over the ratio in the alpha state. In other words we have 48 more protons out of two million, so where all of your carbonyls are available to absorb a photon because remember when you apply a photon it can either kick a nucleus up from the ground state to the first from the alpha state to the beta state or down from the beta state to the alpha state. So it's only that differential population, only that 48 out of two million that are available to absorb. If we apply a higher magnetic field it only gets linearly or almost linearly better. At 117,500 gauss, remember that's our 500 megahertz then we only get to an N beta over an N alpha, in other words a relative population of point again four nines, .999919. In other words it only gets a little bit better. It's only 81 protons out of two million. So we are damned by the low energies. We are damned by the low differences in population and this is why NMR compared to other spectroscopic techniques is very insensitive and why it took a long time to develop. Next time we'll talk about how this NMR spectrometer works, how we absorb our energies and then how we translate that into a spectrum and I'll also talk a little bit maybe about some of the aspects of the spectrum. ------------------------------44553e5ef327--
B2 nmr spin megahertz state coupling nuclear Chem 203. Organic Spectroscopy. Lecture 07. Introduction to NMR Spectroscopy, Part 1 66 5 Cheng-Hong Liu posted on 2015/01/25 More Share Save Report Video vocabulary